28x-(-30x^2)-32=0

Solution for 28x-(-30x^2)-32=0 equation:

28x-(-30x^2)-32=0

We get rid of parentheses

30x^2+28x-32=0

a = 30; b = 28; c = -32;
Δ = b2-4ac
Δ = 282-4·30·(-32)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-68}{2*30}=\frac{-96}{60}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+68}{2*30}=\frac{40}{60}
=2/3
$